The answer we got was 3/12 so 1/4 or 25%. We got this by making a tree diagram if the die landed on a even number or odd number. If the die landed on a even number, there is only a 1/6 chance of getting a 2. If you roll and odd number, there's a 2/6 chance to get a 2. So 1/6 + 2/6 is 3/12.
T'was very simple. Once we found out that the top and bottom numbers on the die were doubled every time an odd number was rolled and then the opposite for an even number, the tree diagram would be of the two die, then the six faces, and since you roll each one twice, we put another branch off from the first roll on each number. We did this for both die then we counted the amount of single numbers and we found the probability is 8/80.
If you roll an odd number(1/6 chance), then you'll get a 2/6 chance of rolling a two in your second roll. But if you roll an even number (4/6), then it becomes a 1/6 chance to roll a 2.
At first I was ridiculously confused, mostly because probability is not one of my best units in math.. I took a look at what the other groups came up with, which was no help. So I tried it my own way. The way I thought it should work out. I believe there was only one die, so I listed each number on the die onto the tree diagram, and then added 6 more branches for each outcome, and what the numbers would change to after the number was rolled. For example: if the number 1 rolled on the die; the 1=2, 2=2, 3=6, 4=4, 6=6, and 8=8.(odd #'s=doubled, even #'s=halved) so the total probability of rolling a two with the changes would be 8/36 total outcomes, which would be about 22%, as well as 22 2/9 in fraction form
Talha Danyal and Nauman:
ReplyDeleteThe answer we got was 3/12 so 1/4 or 25%. We got this by making a tree diagram if the die landed on a even number or odd number. If the die landed on a even number, there is only a 1/6 chance of getting a 2. If you roll and odd number, there's a 2/6 chance to get a 2. So 1/6 + 2/6 is 3/12.
T'was very simple. Once we found out that the top and bottom numbers on the die were doubled every time an odd number was rolled and then the opposite for an even number, the tree diagram would be of the two die, then the six faces, and since you roll each one twice, we put another branch off from the first roll on each number. We did this for both die then we counted the amount of single numbers and we found the probability is 8/80.
ReplyDeleteIt is pretty much 10%.
ReplyDeleteIf you roll an odd number(1/6 chance), then you'll get a 2/6 chance of rolling a two in your second roll. But if you roll an even number (4/6), then it becomes a 1/6 chance to roll a 2.
ReplyDeleteAt first I was ridiculously confused, mostly because probability is not one of my best units in math.. I took a look at what the other groups came up with, which was no help. So I tried it my own way. The way I thought it should work out. I believe there was only one die, so I listed each number on the die onto the tree diagram, and then added 6 more branches for each outcome, and what the numbers would change to after the number was rolled. For example: if the number 1 rolled on the die; the 1=2, 2=2, 3=6, 4=4, 6=6, and 8=8.(odd #'s=doubled, even #'s=halved) so the total probability of rolling a two with the changes would be 8/36 total outcomes, which would be about 22%, as well as 22 2/9 in fraction form
ReplyDeleteI posted that comment this morning because when I tried last night it wouldn't let me sign in, therefore I wasn't able to publish it.
ReplyDelete